Mario Rafael’s Post

🎯 Day 19 of success hashtag hashtag hashtag #problemsolving ! Solved a problem on LeetCode Find the sum of nodes values GitHub Link=https://lnkd.in/gSjvrysr Hard to learn but useful for future hashtag hashtag #100daysofcode hashtag hashtag #100daysofcodechallenge hashtag hashtag #codinglife hashtag #100daysof codingchallenge hashtag #problemsolving hashtag #106DaysOfCode!

I’m excited to share my latest project: TweetExtractor, a graphical user interface application designed to extract detailed information from Twitter profiles and tweets! With TweetExtractor, users can easily access: Profile Insights: Name and Username Bio and Location (if available) URL (if available) Joining Date on Twitter Birthday (if available) Followers and Following Count Total Tweets and Media Count Total Tweets Liked by the User Pinned Tweet (if available) Profile and Cover Images (high-quality downloads) Verification Status: Blue, Grey, Gold ticks with verification history and affiliated accounts Tweet Details: Tweet Content and Date Engagement Metrics: Replies, Reposts, Likes, and Bookmarks Total Quote Count and Views (if available) Tweeted By (Name , Username) with downloadable profile picture Affiliated Logos (if available) with clickable user IDs for more info Batch Download options for images and videos from tweets Download the latest release from GitHub repository [ https://lnkd.in/dPbxFFU2 ] #TweetExtractor #TwitterAPI #XApi

#51 //HERE'S IN THE PROGRAM WE FIND THE #PERMUTATION (NPR) BY USING #FUNCTIONS #EXPLANATION in the program we find the permutation of the n & r #permutation it is a probability que basically in the que we find the ' npr ' according to the formula like #formula 1) npr= n! / (n-r)! #LOGIC 1) simply make a functions according to each needed value ( eg.n!,r! ) 2) make main function and arrange all function 3) call the functions one by one according to the formula #github https://lnkd.in/gCvpVGYH #twitter https://lnkd.in/grdsWru9 #sourcecode⬇ #include <stdio.h> int n, r; int sum = 1; int num = 1; void get() {   int i;   printf("Enter the value of n:");   scanf("%d", &n);   for (i = n; i >= 1; i--) {     sum *= i;   }   return; } void nr() {   int j;   printf("Enter the value of r:");   scanf("%d", &r);   int t = n - r;   for (j = t; j >= 1; j--) {     num *= j;   }   return; } int main() {   get();   nr();   int npr = sum / num;   printf("%d", npr);   return 0; } #img⬇

Come Funziona Threads

4 years ago I started indiehacking, building and launching various projects on the internet. Many have failed, but I've had a small bit of success. The very first product I launched is still active today and has made around $20k in total revenue. And today, I get to share more about how it started and my journey here, including: - building MVPs in 2-weeks - growing a Twitter audience of 42k - burning out trying to find "the"product Read the full interview on Indie Hackers here:

🎯 Day 14 of success hashtag #problemsolving ! Solved a problem on LeetCode Path with maximum gold GitHub Link=https://lnkd.in/gSjvrysr Hard to learn but useful for future hashtag #100daysofcode hashtag hashtag #100daysofcodechallenge hashtag hashtag #codinglife hashtag hashtag #100daysof codingchallenge hashtag hashtag #problemsolving hashtag hashtag #106DaysOfCode!

#49 //HERE'S IN THE PROGRAM WE FIND THE #COMBINATION (NCR) BY USING #FUNCTIONS #EXPLANATION in the program we find the combination of the n & r #combination it is a probability que basically in the que we find the ' ncr ' according to the formula like #formula 1) ncr= n! / r!*(n-r)! #LOGIC 1) simply make a functions according to each needed value ( eg.n!,r! ) 2) make main function and arrange all function 3) call the functions one by one according to the formula #github https://lnkd.in/gCvpVGYH #twitter https://lnkd.in/grdsWru9 #sourcecode⬇ #include<stdio.h> int r,n,x,y,z; void l() {   x=1;   printf("Enter the value of n!:");   scanf("%d",&n);   for (int i=n;i>=1;i--)   {     x=x*i;   }   return; } void c() {   y=1;   printf("Enter the value of r!:");   scanf("%d",&r);   for (int j=r;j>=1;j--)   {     y=y*j;   }   return; } void nr() {   int t=n-r;   z=1;   for (int k=t;k>=1;k--)   {     z=z*k;   }    return; } int main() {   l();   c();   nr();   int ncr=x/(y*z);   printf("The combination result is=%d",ncr);   return 0; } #img⬇

#9 //HERE'S A PROGRAM TO ACCESS ANY (UNLIMITED) NUMBER OF ARITHMETIC TABLE HERE WE USE FRAMEWORK TO MAKE IT SMALL & IT IS A 12 LINE CODE ONLY !!! #github https://lnkd.in/gCvpVGYH #twitter https://lnkd.in/grdsWru9 #sourcecode ⬇ #include<stdio.h> int main() {   int n,i;   printf("Enter the first digit of number:");   scanf("%d",&n);   for(int i=1;i<=10;i++)     {       int mul=i*n;       printf("%d * %d = %d\n",n,i,mul);     }     return 0; } #img ⬇

Is your school looking to move away from using X (Twitter)? 🤔 We have created Chatter to combat current issues with X. Find out more about what it is, its features and how you can get it for your school 👇 #Education #Chatter #School

X-odus: What’s the Best Alternative to Twitter? With recent changes on X/Twitter, many are exploring alternatives. BlueSky has seen a surge in user registrations, while Mastodon remains a strong contender. But here’s the good news: you don’t have to choose between them. Thanks to their decentralized infrastructure, BlueSky and Mastodon are interoperable. This means you can use both platforms seamlessly, accessing Mastodon content directly within BlueSky—and vice versa. Here’s how: On BlueSky, simply follow ap.brid.gy. That’s it! This lets you engage with the entire Fediverse, the network powering Mastodon and other decentralized apps. More information: https://fed.brid.gy/docs So, the only decision left is: are you ready to make the switch?