🚀 LeetCode Daily Challenge 6/100 🚀 📊 Medium 🎯 Problems: Rotate List, Remove Duplicates from Sorted List II 💡 Solutions: - Remove Duplicates from Sorted List II --> Iterate through the linked list to find duplicate values --> if a value is the same as the next value, add it to a set called duplicates --> Iterate through the linked list again --> for each node, if its value is not in duplicates, add it to the new linked list --> return the new linked list, or null if there are no non-duplicate values. - Rotate List --> find the length of the linked list --> calculate the actual rotation amount k by taking k % length --> if k is 0 or the linked list is empty, return the original linked list --> move the fast pointer k steps forward --> move both fast and slow pointers until fast reaches the end of the linked list --> set the next of the end node to the head node to form a circular linked list --> update the head to the node next to the slow pointer and set the next of slow to null to break the loop. 🚧 Complexity Analysis: - Remove Duplicates from Sorted List II Time complexity: O(n), where n is the number of nodes in the linked list. Space complexity: O(n) due to the set duplicates potentially containing all unique values in the linked list. - Rotate List Time complexity: O(n), where n is the number of nodes in the linked list. Space complexity: O(1) #LeetCode #DailyChallenge #Medium #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft #Connections #Engineering #STEM #TechTrends #Innovation #SoftwareEngineering #Coding
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🚀 LeetCode Daily Challenge 5/100 🚀 📊 Hard 🎯 Problem: Minimum Window Substring 💡 Solution: - Solution uses a sliding window approach to find the minimum window in string s that contains all characters in string t. It initializes a left and right pointer to track the window boundaries and moves the right pointer to expand the window until it contains all characters of t. Once all characters are found, it moves the left pointer to shrink the window while maintaining the constraint, updating the minimum window size if necessary. 🚧 Complexity Analysis: Time complexity: O(n), where n is the length of string s. Space complexity: O(m), where m is the number of unique characters in string t. This is for a moment the hardest task to understand for me somehow, took 18 hours from start just to understand clearly how to use sliding window approach #LeetCode #DailyChallenge #Medium #LRUCache #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft
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🚀 Today, I've decided to take a break from tackling medium and hard problems and instead focused on solving a plethora of easy tasks, particularly in the realms of arrays and binary trees. It's been a refreshing change of pace, allowing me to solidify my understanding of foundational concepts and enjoy the satisfaction of swift victories. Here's to the joy of mastering the basics! 🌟 #LeetCode #DailyChallenge #Medium #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft #Connections #Engineering #STEM #TechTrends #Innovation #SoftwareEngineering #Coding
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🚀 LeetCode Daily Challenge 4/100 🚀 📊 Medium 🎯 Problems: LRU Cache, Partition List, Reverse Linked List II 💡 Solutions: - Implemented LRU Cache using a Map to store key-value pairs and maintain the order of recently used items. - For Partition List, split the linked list into two parts, one with nodes less than x and the other with nodes greater than or equal to x. - Reverse Linked List II involves reversing a sublist of a linked list between two specified positions. 🚧 Complexity Analysis: LRU Cache: Time Complexity O(1) for both get and put operations, Space Complexity O(n) where n is the capacity of the cache. Partition List: Time Complexity O(n), Space Complexity O(1). Reverse Linked List II: Time Complexity O(n), Space Complexity O(1). #LeetCode #DailyChallenge #Medium #LRUCache #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft
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🚀 LeetCode Daily Challenge 14/100 🚀 📊 Medium 🎯 Problems: Letter Combinations of a Phone Number 💡 Solutions: - Letter Combinations of a Phone Number --> Create a map to store all chars for each digit --> Create a recursion function ----> It will take input string of digits 1st digit as current ----> It will take corresponding chars from digits map we created before ----> For each of the chars in the array it will call a new function with current string + new char and sliced array ----> Base case - if no more digits left it will push current string to the array and return 🚧 Complexity Analysis: - Letter Combinations of a Phone Number Time complexity: O(4^N), where N is the number of digits in the input string. This is because each digit can represent up to 4 letters (in the case of digits 7, 8, and 9), so for each digit, there are 4 recursive calls, leading to a total of 4^N possible combinations. Space complexity: O(4^N), as the recursion depth can go up to N, and at each level of recursion, a new combination of letters is created, potentially leading to 4^N combinations in total stored in the result array. #LeetCode #DailyChallenge #Medium #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft #Connections #Engineering #STEM #TechTrends #Innovation #SoftwareEngineering #Coding #OpenToWork #Hiring #SoftwareEngineer #Tesla #SpaceX #Netflix #Alphabet #Graph #Graphs #Dfs #Bfs #BinarySearch #Array
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🚀 LeetCode Daily Challenge 23/100 🚀 📊 Medium 🎯 Problems: Unique Paths II 💡 Solutions: - Unique Paths II --> 2 nested loops --> Iterate through matrix ----> If x === 0 and y > 0 we can check prev cell and if it is OBS - curr cell is equal 0 becase we cannot reach this cell from above and left, else - 1 ----> If x > 0 and y === 0 we can check cell above and if it is OBS - curr cell is equal 0 because we cannot reach this cell from above and left, else - 1 ----> if x > 0 and y > 0 we can check cell above and left - if both of them are OBS - cell is equal 0, if one of them is OBS and another is not - cell is equal not OBS cell --> Return matrix[end][end] 🚧 Complexity Analysis: - Unique Paths II Time Complexity: O(n * m), where n is the number of rows and m is the number of columns. Space Complexity: O(1) because the solution modifies the input grid in place without using additional data structures besides a few variables for iteration. Please share Your own solution and improvements suggestions in the comment section 💕 #LeetCode #DailyChallenge #Medium #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft #Connections #Engineering #STEM #TechTrends #Innovation #SoftwareEngineering #Coding #OpenToWork #Hiring #SoftwareEngineer #Tesla #SpaceX #Netflix #Alphabet #Graph #Graphs #Dfs #Bfs #BinarySearch #Array #Spotify #Data #OOP #NodeJS #JavaScript #TypeScript #React #Angular #Engineer #DynamicProgramming #DP
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🚀 LeetCode Daily Challenge 11/100 🚀 📊 Medium 🎯 Problems: Game of Life, Spiral Matrix 💡 Solutions: - Game of Life --> Iterate over each cell in the board and count the number of live neighbors for each cell. --> Based on the number of live neighbours and the current state of the cell, it determines the next state of the cell and updates the board array accordingly. - Spiral Matrix --> Iteratively extrac the elements from the matrix in a spiral pattern. --> Use a flag variable to alternate between moving horizontally and vertically along the edges of the matrix. --> Keep track of the current row to know when to switch direction. The extracted elements are stored in the result array, which is then returned as the final result. 🚧 Complexity Analysis: - Game of Life Time complexity: O(m*n), where m is the number of rows and n is the number of columns in the board. Space complexity: O(m*n). This is because the nextState array is a copy of the board array, so it requires the same amount of space. - Spiral Matrix Time complexity: O(m*n), where m is the number of rows and n is the number of columns in the matrix. Space complexity: space complexity of the function is O(mn). #LeetCode #DailyChallenge #Medium #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft #Connections #Engineering #STEM #TechTrends #Innovation #SoftwareEngineering #Coding #OpenToWork #Hiring #SoftwareEngineer #Tesla #SpaceX #Netflix #Alphabet
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Challenging Myself: Participating in LeetCode Contests 🏆 #Connections Ready to test your coding skills against the best in the world? I recently signed up for the 394th LeetCode Weekly Contest and the 129th LeetCode Biweekly Contest. These events attract top programmers globally, offering a chance to compete and learn in a high-stakes coding environment. Why join LeetCode contests? 1. Benchmarking Skills: Compete against top talent to gauge your coding prowess and identify areas for growth. 2. Learning Experience: Solve challenging problems under time pressure, learning new techniques along the way. 3. Community Engagement: Connect with fellow developers, share insights, and collaborate in a supportive environment. 4. Personal Growth: Overcome challenges, improve under pressure, and grow as a coder. Recap of Previous Challenges 📝 In preparation, I spent over 20 days on LeetCode, tackling problems across various difficulty levels. Each solved problem deepened my understanding and honed my skills. Leetcode Challenge Conclusion 🎉 Registering for these contests marks a milestone in my coding journey. I'm excited for the challenges ahead and the opportunity to grow alongside fellow enthusiasts. Ready to join me? Let's push our limits and unleash our coding potential! See you at the contests! #LeetCode #DailyChallenge #Medium #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft #Connections #Engineering #STEM #TechTrends #Innovation #SoftwareEngineering #Coding #OpenToWork #Hiring #SoftwareEngineer #Tesla #SpaceX #Netflix #Alphabet #Graph #Graphs #Dfs #Bfs #BinarySearch #Array #Spotify #Data #OOP #NodeJS #JavaScript #TypeScript #React #Angular #Engineer
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𝐂𝐨𝐝𝐢𝐧𝐠 𝐈𝐧𝐭𝐞𝐫𝐯𝐢𝐞𝐰 𝐐𝐮𝐞𝐬𝐭𝐢𝐨𝐧: 𝐂𝐥𝐢𝐦𝐛𝐢𝐧𝐠 𝐍 𝐬𝐭𝐚𝐢𝐫𝐬 𝐰𝐢𝐭𝐡 𝐩𝐨𝐬𝐬𝐢𝐛𝐥𝐞 𝐮𝐧𝐢𝐪𝐮𝐞 𝐰𝐚𝐲𝐬 𝐚𝐧𝐝 𝐗 𝐩𝐨𝐬𝐬𝐢𝐛𝐥𝐞 𝐬𝐭𝐞𝐩 𝐬𝐢𝐳𝐞𝐬. 𝐓𝐡𝐞 𝐏𝐫𝐨𝐛𝐥𝐞𝐦: Imagine a staircase with 𝐍 steps, and you have a set of positive integers 𝐗 representing the possible step sizes. Your mission? Find the number of unique ways to climb the staircase, considering that the order of steps matters. For instance, if 𝐍 = 𝟒 and 𝐗 = {𝟏, 𝟐}, there are 𝟓 𝐮𝐧𝐢𝐪𝐮𝐞 𝐰𝐚𝐲𝐬 to ascend: 1, 1, 1 2, 1, 1 1, 2, 1 1, 1, 2 2, 2 𝐓𝐡𝐞 𝐒𝐨𝐥𝐮𝐭𝐢𝐨𝐧: 𝐃𝐲𝐧𝐚𝐦𝐢𝐜 𝐏𝐫𝐨𝐠𝐫𝐚𝐦𝐦𝐢𝐧𝐠 In essence, 𝐭𝐡𝐢𝐬 𝐩𝐫𝐨𝐛𝐥𝐞𝐦 𝐢𝐬 𝐬𝐢𝐦𝐢𝐥𝐚𝐫 𝐭𝐨 𝐭𝐡𝐞 𝐅𝐢𝐛𝐨𝐧𝐚𝐜𝐜𝐢 𝐬𝐞𝐫𝐢𝐞𝐬, let's explain: 𝐁𝐚𝐬𝐞 𝐂𝐚𝐬𝐞𝐬: climbingWays[0] = 1: No steps (already at the top). climbingWays[1] = 1: Only one step (take it!). 𝐃𝐲𝐧𝐚𝐦𝐢𝐜 𝐏𝐫𝐨𝐠𝐫𝐚𝐦𝐦𝐢𝐧𝐠 𝐌𝐚𝐠𝐢𝐜: Initialize an array climbingWays to store ways to reach each step. For each step i from 2 to N: Consider all possible step sizes from X. Update climbingWays[i] by adding ways from previous steps: climbingWays[i] += climbingWays[i - x]. 𝐓𝐢𝐦𝐞 𝐂𝐨𝐦𝐩𝐥𝐞𝐱𝐢𝐭𝐲: O(N * |X|) 𝐖𝐡𝐲 𝐈𝐭 𝐌𝐚𝐭𝐭𝐞𝐫𝐬: This problem mirrors real-world scenarios (like climbing stairs) and teaches us efficient problem-solving. Dynamic programming optimizes repetitive calculations, making it a powerful tool for interview success. 𝐒𝐡𝐚𝐫𝐞 𝐭𝐡𝐞 𝐊𝐧𝐨𝐰𝐥𝐞𝐝𝐠𝐞: Tag your coding buddies, and let’s celebrate unraveling the enigma of interview questions! 🤓💡 #Coding #Interviewprep #DynamicProgramming #Algorithm #CodingInterviews #JavaScript #ProgrammingTips #SoftwareDevelopment #TechCommunity #CodeSnippets #LinkedInLearning #Angular #Nodejs #Meanstack #Typescript #Google #Amazon #Meta #Facebook Feel free to customize and share! Let’s inspire others to embrace the challenge and conquer those coding staircases! 🎉
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✅Are you ready to level up your skills and land a job at a leading tech company? ✅Take the first step by mastering the programming languages favored by industry giants like Google, Amazon, and Facebook! ✅Don't miss out on the opportunity to acquire the skills sought after by the biggest names in tech. ✅Start your journey today and pave the way for a rewarding career in the digital age! ✅Ready to get started? Click the link below to explore our programs: https://lnkd.in/gg9zAK8 #Python #JavaScript #Java #Swift #TechLanguages #ProgrammingSkills #DeveloperCommunity #TechCareer #CodingBootcamp #SoftwareEngineering #WebDevelopment #MobileAppDevelopment #DataTrained
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👨💻 Over a month of daily LeetCode challenges: 🚀 Excited to share a milestone in my coding journey! For the past month, I've dedicated myself to solving a LeetCode problem every day. It's been an amazing experience that has truly transformed me as a problem solver. Through these challenges, I've honed my skills, improved my algorithmic thinking, and gained confidence in tackling complex problems. However, as with any journey of growth, there's always more to learn. I've identified Tries and Heaps as my current weaknesses, and I'm eager to dive deeper into these topics to strengthen my understanding. I believe that the best way to learn is through sharing and collaboration. So, I'd love to hear from fellow developers: What Data Structures or concepts do you find most challenging? How do you approach mastering them? Let's start a conversation and learn from each other's experiences! 💬💡 Here's to embracing the journey of continuous learning and conquering new coding horizons together! 🌟 #LeetCode #DailyChallenge #Medium #LinkedList #Algorithms #SoftwareDevelopment #Developer #Tech #Coding #DataStructures #JavaScript #TypeScript #React #NodeJS #Java #ProblemSolving #CodeChallenge #Recruiters #BigTechCompanies #FAANG #MAMAA #Google #Amazon #Meta #Microsoft #Connections #Engineering #STEM #TechTrends #Innovation #SoftwareEngineering #Coding #OpenToWork #Hiring #SoftwareEngineer #Tesla #SpaceX #Netflix #Alphabet #Graph #Graphs #Dfs #Bfs #BinarySearch #Array #Spotify #Data #OOP #NodeJS #JavaScript #TypeScript #React #Angular #Engineer #DynamicProgramming #DP
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